Kelvinlev Neutral Newbie January 29, 2012 Share January 29, 2012 A table and 3 chairs cost $2348. The table costs $264 more than 1 chair. Find the cost of the table. Paisei, think here think there, cannot find, and will get more confused thereafter, algebra not applicable for P4 students, right? ↡ Advertisement Link to post Share on other sites More sharing options...
1fast1 Supersonic January 29, 2012 Share January 29, 2012 (edited) A table and 3 chairs cost $2348. The table costs $264 more than 1 chair. Find the cost of the table. Paisei, think here think there, cannot find, and will get more confused thereafter, algebra not applicable for P4 students, right? Cost of 1 table = cost of 1 chair + 264 dollars. So spending 2348 dollars is equivalent to buying 4 chairs plus spending another 264 dollars. Cost of 4 chairs = 2348 - 264 = 2084 dollars Cost of 1 chair = 521 dollars. Cost of 1 table = 521 + 264 = 785 dollars. Edited January 29, 2012 by Turboflat4 Link to post Share on other sites More sharing options...
Speedsun Clutched January 29, 2012 Share January 29, 2012 A table and 3 chairs cost $2348. The table costs $264 more than 1 chair. Find the cost of the table. Paisei, think here think there, cannot find, and will get more confused thereafter, algebra not applicable for P4 students, right? $785 for the table. Link to post Share on other sites More sharing options...
To_be_advised Neutral Newbie January 29, 2012 Share January 29, 2012 if chair = x, then table = x + 264. 2348 = 4x + 264 2348-264 = 4x 2084 = 4x 2084 / 4 = x 521 = x table cost = x + 264 = 521 + 264 = 785 Link to post Share on other sites More sharing options...
Kelvinlev Neutral Newbie January 29, 2012 Author Share January 29, 2012 thanks a lot.....brain not able to function like last time liao.......... Link to post Share on other sites More sharing options...
Kelvinlev Neutral Newbie January 29, 2012 Author Share January 29, 2012 haha, you steady, give me ans only.... ↡ Advertisement Link to post Share on other sites More sharing options...
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