Math Help , please

[Kelvinlev]

A table and 3 chairs cost $2348. The table costs $264 more than 1 chair.

Find the cost of the table.

 

Paisei, think here think there, cannot find, and will get more confused thereafter, algebra not applicable for P4 students, right?

 

 

[1fast1]

A table and 3 chairs cost $2348. The table costs $264 more than 1 chair.

Find the cost of the table.

 

Paisei, think here think there, cannot find, and will get more confused thereafter, algebra not applicable for P4 students, right?

 

Cost of 1 table = cost of 1 chair + 264 dollars.

 

So spending 2348 dollars is equivalent to buying 4 chairs plus spending another 264 dollars.

 

Cost of 4 chairs = 2348 - 264 = 2084 dollars

 

Cost of 1 chair = 521 dollars.

 

Cost of 1 table = 521 + 264 = 785 dollars.

Edited January 29, 2012 by Turboflat4

[Speedsun]

A table and 3 chairs cost $2348. The table costs $264 more than 1 chair.

Find the cost of the table.

 

Paisei, think here think there, cannot find, and will get more confused thereafter, algebra not applicable for P4 students, right?

 

$785 for the table.

 

[To_be_advised]

if chair = x, then table = x + 264.

 

2348 = 4x + 264

2348-264 = 4x

2084 = 4x

2084 / 4 = x

521 = x

 

table cost

= x + 264

= 521 + 264

= 785

[Kelvinlev]

thanks a lot.....brain not able to function like last time liao..........

 

 

[Kelvinlev]

haha, you steady, give me ans only....